By: Rohan Pal, The Mobile Indian, New Delhi
Last updated : April 17, 2018 5:01 pm
The smartphone has been found listed on Chinese regulatory, TENAA revealing some key specifications.
Nubia recently launched the Z18 Mini smartphone in China and now it seems to be working on its elder sibling, the Z18. The smartphone has been found listed on Chinese regulatory, TENAA revealing some key specifications.
The smartphone with model number NX606J has been certified on TENAA. The listing reveals some images of the upcoming smartphone, which looks a bit identical to the recently-launched Nubia Z18 Mini. The listing reveals that the smartphone will feature a 5.99-inch Full HD+ display with a screen resolution of 2160 x 1080 pixels.
The device will be backed by a 6GB and 8GB of RAM, while there will be 64GB and 128GB storage variants. On the hardware front, the device will be powered by the latest Qualcomm Snapdragon 845 chipset along with Adreno 630 GPU. The Nubia Z18 will feature a dual-camera setup at the rear with a combination of 24-megapixel primary and a secondary sensor. For the front, there will be an 8-megapixel shooter for selfies and video calling.
The smartphone 3350mAh battery and it will run on Android 8.0 Oreo. There will be a fingerprint sensor at the back panel. On the connectivity front, the smartphone features 4G VoLTE, WiFi 802.11 ac, Bluetooth 5.0, GPS, USB Type-C port and dual SIM support. The phone measures 148.58 x 72.54 x 8.55mm and weighs 172 grams.
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